[OCR] 4

Topic: Atomic Structure

(a) Explain why gravitational potential is always negative whereas electric potential can have positive and negative values, given that both potentials are zero at infinity.\n$\qquad$\n$\qquad$\n$\qquad$\n$\qquad$\n$\qquad$\n$\qquad$\n$\qquad$\n$\qquad$\n$\qquad$\n$\qquad$ [11.0m]

Part 1: (b) Fig. 4.1 shows how the gravitational potential $\phi$ from the surface of a planet varies with distance $r$ from the centre of the planet.\n\nFig. 4.1 [1m]

Part 2: (i) A moon orbits the planet. The mass of the moon is $1.48 \times 10^{23} \mathrm{~kg}$ and its orbital radius is $1.07 \times 10^{6} \mathrm{~km}$.\n\nUsing Fig 4.1, calculate [1m]

Part 3: 1. the orbital speed of the moon,\norbital speed $=\ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots$$ [2m]

Part 4: 2. the total energy of the moon. [2m]

Part 5: (ii) A rock is projected vertically upwards with a speed of $45 \mathrm{~km} \mathrm{~s}^{-1}$ from the surface of the planet. The resistive forces on the rock by the planet's atmosphere are negligible.\n\nUsing Fig 4.1, [1m]

Part 6: 1. show, with clear working, that the rock will not escape the planet, [2m]

Part 7: 2. determine the maximum distance of the rock from the surface of the planet.\n$$\text { distance }=\ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots$$ [2m]

Review

You're all caught up!

Similar Problems

OCR
Atomic Structure
Particle A of mass $9 m$ and particle $B$ of mass $m$ travel towards each other along a smooth horizontal surface in a straight line and collide head-on. The initial speed of particle A before the collision is $u$.\n\nIn Fig. 1.1, the variation with time $t$ of momentum $p$ is shown from $t=0$ to $t=3 T$ for particle $A$ and from $t=0$ to $t=T$ for particle $B$.\n<img src="/serve/img-0_20250331210529562504.jpeg">\nFig. 1.1
OCR
Atomic Structure
A uniform square box with sides 0.80 m and mass 2.0 kg is at rest on the ground. One end of a light rope is attached to the box and the other end is attached to the wheel of a motor. The motor applies a constant clockwise torque of 5.0 N m on the wheel of radius 0.20 m .\n\nAt the instant shown in Fig. 2.1, the rope is taut and it makes an angle of $\theta=20^{\circ}$ with the vertical side of the box. The system remains in equilibrium.\n<img src="/serve/img-1_20250331210529564678.jpeg">\nFig. 2.1
OCR
Atomic Structure
A bob of mass 1.5 kg is attached to a string of negligible mass and of length 25.0 cm . The other end of the string is fixed to point $X$ of an inverted " $L$ " structure of arm length $d$. The structure is fixed to the centre of a rotating disc of radius 8.0 cm .\n\nWhen the disc rotates with an angular velocity $\omega$, the string makes at an angle $\theta$ to the vertical as shown in Fig. 3.1.\n<img src="/serve/img-2_20250331210529565031.jpeg">\nFig. 3.1
OCR
Atomic Structure
A transverse wave on a rope is travelling to the right. Fig. 5.1 shows the waveform at a particular time. Particles Q, R, S, T, U and V are labelled.\n<img src="/serve/img-4_20250331210529567662.jpeg">\nFig. 5.1
OCR
Atomic Structure
Fig 6.1 shows a miniature E10 filament light bulb with a rating of $6.0 \mathrm{~V}, 3.0 \mathrm{~W}$.<img src="/serve/img-5_20250331210529568075.jpeg">\nFig. 6.1
OCR
Atomic Structure
A medical treatment makes use of a sample of americium-240 that emits alpha particles to kill cancer cells. In one such treatment, a total energy of 1140 J is applied to a tumour of mass 0.500 kg . At the start of the treatment, the mass of the americium-240 sample is $2.00 \times 10^{-9} \mathrm{~kg}$.\n\nAmericium-240 has a half-life of 50.2 hours, and it decays by emitting an alpha particle of kinetic energy 5.71 MeV .
Atomic Structure
Read the passage below and answer the questions that follow.\nDespite the increasing popularity of laser printers