[2023 RI Y6 TP] .
Topic: Integration techniques
. [5.0m]
Part 1: Find $\int \sin^2 x \, dx$ [2m]
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Part 2: Hence or otherwise, show that $ \int x \sin^2 x \, dx = \frac{1}{4} x^2 - \frac{1}{4} x \sin 2x - \frac{1}{8} \cos 2x + c$. [3m]
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